TM 5-814-9
(b) Maximum bath overflow volume, V2:
V8 = Q8 x K = l80 gpm x 60 min
V8 = 10800 gal (40878L)
V2
= bath overflow rate x (total wash
period plus clean-up)
(i) Pavement runoff volume, V9:
V2
= Q2 x T2 = 960 gpm x 3300 min
= 3168000 gal (11990880 L)
V2
V9 = pavement runoff rate x storm
duration
(c) Maximum volume from washstations, V3:
5
V9 = Q9 x T = 1818 gpm x 60 min
V3
= washstation flow rate x peak
wash period
V9 = 109080 gal (412868 L)
V3
= Q3 x Tw = 720 gpm x 3240 min
(J) Rainfall volume added to basins, V10:
V3
= 2332800 gal (8829648 L)
V10= Rainfall rate x storm duration
(d) Maximum volume from entrance trench
V10= Q10 x TS = 4937 gpm x 60 min
flusher, V4:
V10= 296220 gal (1121193 L)
V4
= entrance trench flusher flow rate
x clean-up period
(k) Summary of average daily volume. Table
A-4 summarizes the computed average
V4
= Q4 x K = 75 gpm x 60 min x 3
daily volumes for the stated design
cleanups
conditions at Fort Swampy.
V4
= 13500 gal (51,098 L)
Total average daily volume for facility Vavg: The designer
(e) Maximum volume from bath flushing, V5:
uses equation 6-2, however, designer chooses not to include
pavement runoff volume, V9 or rainfall volume on basins, V10
V3
= bath flusher flow rate x cleanup
Designer also assumes that flush water will be withdrawn from
period
the washwater supply basin and therefore, V1, V5, and V6 are
included in the computation. Then,
V5
= Q5 x K = 3000 gpm x 60 min
Vavg = U1V1+U2V2+U3V3+U4V4+U5V5+
V5
= l80000 gal (681300 L)
U6V6 +U7V7 + U8V8
Vavg = l.0(191862) + 0.9 (230400) +
(f) Maximum volume from wash station
0.8(129600) + 0.2(4500) +
flushing. V6:
0.2(180000) + 0.2(54000) +
0.8(21600) + 0.2(10800)
V6
= flusher flow rate x (wash plus
cleanup + two additional clean-
Vavg = 570042 gal (2157609 L)
up periods)
(5) Calculate maximum volume for the peak use
V6
= Q6 x (T1 + 2K)
period, Vmax: The designer computes the vari-
ous component maximum volumes for the
V6
= 225 gpm (3300 min + 2 x 60
following selected peak use conditions:
min)
Clean-up period, K
60 min (1 hr)
V6
= 769500 gal (2912558 L)
Peak use period. Tw
3240 min (55 hr)
Total wash and clean-up, Tt 3300 min (56 hr)
(g) Maximum interior wash water volume,
Storm duration, Ts
60 min (1 hr)
V7:
The designer assumes that one bath fill, B, will be withdrawn
V7
= Interior wash flow rate x wash
from the equalization basin.
period
(a) Maximum bath volume drained, Vl:
V7
= Q7 x T w = 120 gpm x 3240 min
V1
= VB x Number of fills
V7
= 388880 gal (1471608 L)
V1
= 191862 gal x 1
(h) Maximum volume from yard hydrants,
V8:
V1
= 191862 gal (726198 L)
A-14
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